## Arithmetic Reasoning MCQ’S

## Results

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### #1. The total of the ages of Amar, Akbar and Anthony is 80 years. What was the total of their ages three years ago ?

**Option A**

### #2. Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?

**Option B**

Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.

Then, 2x 3y = 77 …(i) and

3x 2y = 73 …(ii)

Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.

Putting y = 17 in (i), we get: x = 13.

### #3. An institute organised a fete and 1/5 of the girls and 1/8 of the boys participated in the same. What fraction of the total number of students took part in the fete ?

**Option C**

### #4. A number of friends decided to go on a picnic and planned to spend Rs. 96 on eatables. Four of them, however, did not turn up. As a consequence, the remaining ones had to contribute Rs. 4 each extra. The number of those who attended the picnic was

**Option A**

### #5. A, B, C, D and E play a game of cards. A says to B, “If you give me three cards, you will have as many as E has and if I give you three cards, you will have as many as D has.” A and B together have 10 cards more than what D and E together have. If B has two cards more than what C has and the total number of cards be 133, how many cards does B have ?

**Option C**

Clearly, we have :

B – 3 = E …(i)

B 3 = D …(ii)

A B = D E 10 …(iii)

B = C 2 …(iv)

A B C D E= 133 …(v)

From (i) and (ii), we have : 2 B = D E …(vi)

From (iii) and (vi), we have : A = B 10 …(vii)

Using (iv), (vi) and (vii) in (v), we get:

(B 10) B (B – 2) 2B = 133 ⇔ 5B = 125 ⇔ B = 25.

### #6. A pineapple costs Rs. 7 each. A watermelon costs Rs. 5 each. X spends Rs. 38 on these fruits. The number of pineapples purchased is

**Option C**

### #7. A woman says, “If you reverse my own age, the figures represent my husband’s age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum.” The woman’s age is

**Option C**

Let x and y be the ten’s and unit’s digits respectively of the numeral denoting the woman’s age.

Then, woman’s age = (10X y) years; husband’s age = (10y x) years.

Therefore (10y x)- (10X y) = (1/11) (10y x 10x y)

⇔ (9y-9x) = (1/11)(11y 11x) = (x y) ⇔ 10x = 8y ⇔ x = (4/5)y

Clearly, y should be a single-digit multiple of 5, which is 5.

So, x = 4, y = 5.

Hence, woman’s age = 10x y = 45 years.

### #8. A girl counted in the following way on the fingers of her left hand : She started by calling the thumb 1, the index finger 2, middle finger 3, ring finger 4, little finger 5 and then reversed direction calling the ring finger 6, middle finger 7 and so on. She counted upto 1994. She ended counting on which finger ?

**Option B**

Clearly, while counting, the numbers associated to the thumb will be : 1, 9,17, 25,…..

i.e. numbers of the form (8n 1).

Since 1994 = 249 x 8 2, so 1993 shall correspond to the thumb and 1994 to the index finger.

### #9. A man has Rs. 480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?

**Option D**

Let number of notes of each denomination be x.

Then, x 5x 10x = 480 ⇔ 16x = 480 ⇔ x = 30.

Hence, total number of notes = 3x = 90.

### #10. What is the product of all the numbers in the dial of a telephone ?

**Option D**