Arithmetic Reasoning MCQ’S


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#1. The total of the ages of Amar, Akbar and Anthony is 80 years. What was the total of their ages three years ago ?

Answer: Option A
Solution: Required sum = (80 – 3 x 3) years = (80 – 9) years = 71 years.

#2. Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?

Answer: Option B

Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.
Then, 2x 3y = 77 …(i) and
3x 2y = 73 …(ii)
Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.
Putting y = 17 in (i), we get: x = 13.

#3. An institute organised a fete and 1/5 of the girls and 1/8 of the boys participated in the same. What fraction of the total number of students took part in the fete ?

Answer: Option C
No explanation is given for this question

#4. A number of friends decided to go on a picnic and planned to spend Rs. 96 on eatables. Four of them, however, did not turn up. As a consequence, the remaining ones had to contribute Rs. 4 each extra. The number of those who attended the picnic was

Answer: Option A

#5. A, B, C, D and E play a game of cards. A says to B, “If you give me three cards, you will have as many as E has and if I give you three cards, you will have as many as D has.” A and B together have 10 cards more than what D and E together have. If B has two cards more than what C has and the total number of cards be 133, how many cards does B have ?

Answer: Option C

Clearly, we have :
B – 3 = E …(i)
B 3 = D …(ii)
A B = D E 10 …(iii)
B = C 2 …(iv)
A B C D E= 133 …(v)
From (i) and (ii), we have : 2 B = D E …(vi)
From (iii) and (vi), we have : A = B 10 …(vii)
Using (iv), (vi) and (vii) in (v), we get:
(B 10) B (B – 2) 2B = 133 ⇔ 5B = 125 ⇔ B = 25.

#6. A pineapple costs Rs. 7 each. A watermelon costs Rs. 5 each. X spends Rs. 38 on these fruits. The number of pineapples purchased is

Answer: Option C

#7. A woman says, “If you reverse my own age, the figures represent my husband’s age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum.” The woman’s age is

Answer: Option C

Let x and y be the ten’s and unit’s digits respectively of the numeral denoting the woman’s age.
Then, woman’s age = (10X y) years; husband’s age = (10y x) years.
Therefore (10y x)- (10X y) = (1/11) (10y x 10x y)
⇔ (9y-9x) = (1/11)(11y 11x) = (x y) ⇔ 10x = 8y ⇔ x = (4/5)y
Clearly, y should be a single-digit multiple of 5, which is 5.
So, x = 4, y = 5.
Hence, woman’s age = 10x y = 45 years.

#8. A girl counted in the following way on the fingers of her left hand : She started by calling the thumb 1, the index finger 2, middle finger 3, ring finger 4, little finger 5 and then reversed direction calling the ring finger 6, middle finger 7 and so on. She counted upto 1994. She ended counting on which finger ?

Answer: Option B

Clearly, while counting, the numbers associated to the thumb will be : 1, 9,17, 25,…..
i.e. numbers of the form (8n 1).
Since 1994 = 249 x 8 2, so 1993 shall correspond to the thumb and 1994 to the index finger.

#9. A man has Rs. 480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?

Answer: Option D

Let number of notes of each denomination be x.
Then, x 5x 10x = 480 ⇔ 16x = 480 ⇔ x = 30.
Hence, total number of notes = 3x = 90.

#10. What is the product of all the numbers in the dial of a telephone ?

Answer: Option D
Solution: Since one of the numbers on the dial of a telephone is zero, so the product of all the numbers on it is 0.