## Speed Time And Distance MCQ’S

## Results

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### #1. Two buses start from a bus terminal with a speed of 20 km/h at interval of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at interval of 8 minutes?

**Option C**

Let Speed of the man is x kmph.

Distance covered in 10 minutes at 20 kmph = distance covered in 8 minutes at (20 x) kmph.

Or,

Or, 200 = 160 8x

Or, 8x = 40

Hence, x = 5kmph.

**Detailed Explanation:**

A _____________M_______________B

A = Bus Terminal.

B = Let meeting point of first bus and the man and this distance is covered by Bus in 10 minutes. I.e. Distance A to be is covered first bus in 10 min. As AB distance can be covered by second bus in 10 minutes as well.

Distance Covered by Bus in 10 min = AB =

Now, M is the Meeting Point of Second Bus with Man. Man covered distance B to M in 8 minutes.

Now, Relative distance of both Man and Bus will be same as both are traveling in opposite direction of each other. Let Speed of the man = x kmph.

Relative speed = 20 x

To meet at Point M, bus and Man has covered the distance (AB) in 8 minutes with relative speed. And Same AB distance is covered by bus in 10 minutes. Thus, Distance covered in 8 minutes with relative speed (20 x) kmph = distance covered by bus in 10 minuted with speed 20 kmph.

### #2. Waking 3/4 of his normal speed, Rabi is 16 minutes late in reaching his office. The usual time taken by him to cover the distance between his home and office:

**Option A**

**1 ^{st} method:**

of usual time = Usual time 16 minutes;

Hence,

of usual time = 16 minutes;

Thus, Usual time = 16 × 3 = 48 minutes.

**2 ^{nd} method:**

When speed goes down to

(i.e. 75%) time will go up to

(or 133.33%) of the original time.

Since, the extra time required is 16 minutes; it should be equated to

of the normal time.

Hence, the usual time required will be 48 minutes.

### #3. Two trains for Mumbai leave Delhi at 6 am and 6.45 am and travel at 100 kmph and 136 kmph respectively. How many kilometers from Delhi will the two trains be together:

**Option C**

Difference in time of departure between two trains = 45 min. =

Let the distance be x km from Delhi where the two trains will be together.

Time taken to cover x km with speed 136 kmph be t hour

and time taken to cover x km with speed 100 kmph (As the train take 45 mins. more) be

Now,

100 ×

= 136t

Or, 25(4t 3) = 136t

Or, 100t 75 = 136t

Or, 36t = 75

Or, t = 75/36 = 2.08 hours

Then, distance x km = 136 × 2.084 = 283.33 km.

### #4. A man takes 6 hours 15 minutes in walking a distance and riding back to starting place. He could walk both ways in 7 hours 45 minutes. The time taken by him to ride back both ways is:

**Option C**

Time taken in walking both the ways = 7 hours 45 minutes ——– (i)

Time taken in walking one way and riding back = 6 hours 15 minutes ———– (ii)

By the equation (ii) × 2 – (i), we have,

Time taken by the man in riding both ways,

= 12 hours 30 minutes – 7 hours 45 minutes

= 4 hours 45 minutes.

### #5. A man completes a certain journey by a car. If he covered 30% of the distance at the speed of 20kmph. 60% of the distance at 40km/h and the remaining of the distance at 10 kmph, his average speed is:

**Option A**

### #6. From two places, 60 km apart, A and B start towards each other at the same time and meet each other after 6 hour. If A traveled with 2/3 of his speed and B traveled with double of his speed, they would have met after 5 hours. The speed of A is:

**Option B**

**A →_______60Km_________← B**

Let the speed of A = x kmph and that of B = y kmph

According to the question;

x × 6 y × 6 = 60

Or, x y = 10 ——— (i)

And,

Or, 10x 30y = 180

Or, x 3y = 18 ———- (ii)

From equation (i) × 3 – (ii)

3x 3y – x – 3y = 30 – 18

Or, 2x = 12

Hence, x = 6 kmph

### #7. A, B and C start together from the same place to walk round a circular path of length 12km. A walks at the rate of 4 km/h, B 3 km/h and C 3/2 km/h. They will meet together at the starting place at the end of:

**Option D**

Time taken to complete the revolution:

A → 12/4 = 3 hours

B → 12/3 = 4 hours

C → 12 × 2/3 = 8 hours

Required time,

= LCM of 3, 4, 8.

= 24 hours.

### #8. Ravi and Ajay start simultaneously from a place A towards B 60 km apart. Ravi’s speed is 4km/h less than that of Ajay. Ajay, after reaching B, turns back and meets Ravi at a places 12 km away from B. Ravi’s speed is:

**Option C**

Ajay →** (x 4) kmph.**

A ________ 60 km _________ B

Ravi → **x kmph.**

Let the speed of Ravi be x kmph;

Hence, Ajay’s speed = (x 4) kmph;

Distance covered by Ajay = 60 12 = 72 km;

Distance covered by Ravi = 60 – 2 = 48 km.

According to question,

### #9. The speed of A and B are in the ratio 3 : 4. A takes 20 minutes more than B to reach a destination. Time in which A reach the destination?

**Option A**

Ratio of speed = 3 : 4

Ratio of time taken = 4 : 3 **(As Speed ∝ **1/Time, **remains constant.)**

Let time taken by A and B be 4x and 3x hour respectively.

Then,

4x – 3x = 20/60

Or, x = 1/3

Hence, time taken by A = 4x

= 4/3 hours.

### #10. A man covers half of his journey at 6 km/h and the remaining half at 3 km/h. His average speed is

**Option C**